SOLUTION: Find the limits of the sequences.
an= cos(n*pi /2)
Thank you so much!
Algebra.Com
Question 579911: Find the limits of the sequences.
an= cos(n*pi /2)
Thank you so much!
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
, , , , and it repeats from then on because cosine is periodic with a period of , so , and so on. In general
, but does not converge. It just keeps flip-flopping between 1 and -1, hitting 0 in between. There is no limit.
RELATED QUESTIONS
Determine if the following series are convergent of divergent. If the series is geometric (answered by KMST)
Find a cofunction with the same value as the given expression: cos pi/15
This is what... (answered by Fombitz)
Some sequences involve a pattern but are not arithmetic. Find the sum of the first... (answered by Edwin McCravy)
Find the surface area, to the nearest tenth, of a cylinder with diameter 5 cm and height... (answered by nerdybill)
Find the midpoint riemann sum for f(x) = cos(2x) on the partition
P =... (answered by richard1234)
Hello everyone, and Merry Christmas!!
Can somebody explain me the difference about these (answered by Alan3354)
Find the exact value of cos^-1{{{(cos(4PI/3))}}}
the possible answers are
a. -PI/3
(answered by jim_thompson5910)
Find all numbers for which the rational expression is undefined.
n^3 - 7n / n^2 - 9
(answered by nerdybill)
What is the Period and Amplitude of 3/4 pi cos (pi)(x)/12 ?
Thank you (answered by Alan3354,robertb)