SOLUTION: I'm working with fraction exponents i.e. #roots. I know how to solve for the variable when it is an exponent, but this is a new lesson where I have to solve for the variable that i

Question 558170: I'm working with fraction exponents i.e. #roots. I know how to solve for the variable when it is an exponent, but this is a new lesson where I have to solve for the variable that is a base.

This what I've tried, but I've hit a dead end.
Problem:
Step 1: or is it
---I got same bases on both sides of the equation and had 4^(3-24) subsitute my value for 40, since (4^3)=64, but I would have to subtract 24 from either the exponent or from the whole side of the equation. Here's where I hit a wall and I don't know what to do after that since I tried to do both of my alternatives.
P.S. This is an excercise to get our feet wet for tomorrow's lesson.
Found 3 solutions by KMST, edjones, mananth:
Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
You don't want addition and/or subtraction. Stick to multiplication, division and powers.
First, division:
--> -->
Now, powers:
--> -->

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
16d^(1/4)=40
d^(1/4)=5/2
d=(5/2)^4=625/16 Take each side to the 4th power.
.
Ed

Answer by mananth(16946)   (Show Source): You can put this solution on YOUR website!

raise to power 4 on both sides

16^4*d= 40^4
d= 40^4/16^4
d=625/16
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