SOLUTION: the sum of the square are two consecutive positive integers is 221. find the integers? i put as the answer 4,5?

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Question 530187: the sum of the square are two consecutive positive integers is 221. find the integers? i put as the answer 4,5?
Answer by jim_thompson5910(28503) About Me  (Show Source):
You can put this solution on YOUR website!
No, you are incorrect since 4^2 + 5^2 = 16+25 = 41


"the sum of the square are two consecutive positive integers is 221" means that x%5E2%2B%28x%2B1%29%5E2=221

Note: in the phrase above, I think you truly mean "the sum of the squares of two consecutive positive integers is 221"



x%5E2%2Bx%5E2%2B2x%2B1=221


x%5E2%2Bx%5E2%2B2x%2B1-221=0


2x%5E2%2B2x-220=0


2%28x%5E2%2Bx-110%29=0


2%28x-10%29%28x%2B11%29=0


x-10=0 or x%2B11=0


x=10 or x=-11


Assuming you want positive integers only, the answer is x=10


So the two integers are 10 and 11


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