SOLUTION: 4) John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area o

Question 52642: 4) John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.
Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex form to find the maximum area.
Answer:
Show work in this space.

Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
THE MAXIMUM AREA OF ANY RECTANGLE IS A SPECIAL RECTANGLE CALLED A SQUARE THUS
X^2=300 OR X=17.320508 FEET.
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