1st 2nd n an differences differences 1 5 0 1 2 5 1 1 3 6 2 1 4 8 3 1 5 11 4 6 15 Since the 2nd differences are all constant we try a 2nd degree polynomial in nSimplifying: Solve that system and get A = , B = , C = 6 So the equation becomes: Substituting n = 20 Substituting n = 21 Answers: , Edwin