SOLUTION: In the arithmetic sequence, the 3rd term is 4 and the 8th term is 49. Find the 1st term, the common difference and the sum of the first ten terms.

Question 484324: In the arithmetic sequence, the 3rd term is 4 and the 8th term is 49. Find the 1st term, the common difference and the sum of the first ten terms.
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!
In the arithmetic sequence, the 3rd term is 4 and the 8th term is 49. Find the 1st term, the common difference and the sum of the first ten terms.



>>...the 3rd term is 4...<<






>>...the 8th term is 49...<<






So we have a system of equations:



Solve by substitution or elimination and get

 and 

first term is -14,

Here is the sequence to 10 terms:

-14, -5, 4, 13, 22, 31, 40, 49, 58, 67 

To get the sum of the first 10 terms, 
we use the formula:













sum =  265

Edwin

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