SOLUTION: The sequence is defined recursively. Write the first four terms. {{{a[1]=2 a[2]=5 and a[n]=a[n-2] - 3a[n-1] for n >= 3}}} I really need some help

Algebra ->  Algebra  -> Sequences-and-series -> SOLUTION: The sequence is defined recursively. Write the first four terms. {{{a[1]=2 a[2]=5 and a[n]=a[n-2] - 3a[n-1] for n >= 3}}} I really need some help       Log On

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Question 46984: The sequence is defined recursively. Write the first four terms.
a%5B1%5D=2+++++++a%5B2%5D=5++++++and+++++a%5Bn%5D=a%5Bn-2%5D+++-+++3a%5Bn-1%5D+++++++++for+n+%3E=+3
I really need some help with this problem please.
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
The sequence is defined recursively. Write the first four terms.
a[1]=2 a[2]=5

and a[n]=a[n-2] - 3a[n-1] for n >= 3
PUT N=3
A3=A1-3A2=2-3*5=2-15=-13
PUT N=4
A4=A2-3A3=5-3*(-13)=5+39=44

I really need some help with this problem please.