SOLUTION: identify the following series as arithmetic , geometric , or neither.
1. 3a + 3a^2 + 3a^3 + 3a^4 +...+ 3a^n +...
2. -3+3-3+3-3+3....
3. n=1 (3+na) >> above this is a si
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Question 446591: identify the following series as arithmetic , geometric , or neither.
1. 3a + 3a^2 + 3a^3 + 3a^4 +...+ 3a^n +...
2. -3+3-3+3-3+3....
3. n=1 (3+na) >> above this is a sideways 8 and a sideways M <<<
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
1. Geometric, common ratio is a.
2. Geometric, common ratio is -1. This series does not converge though, the ratio has to be strictly between -1 and 1 for the series to converge.
3. I presume you mean
)
where 
is the infinity symbol and 
is the Greek uppercase letter sigma. If a is a constant, then the series is
 + (3 + 2n) + (3 + 3n) + ...)
, in which the sequence determined is arithmetic with common difference n.
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