SOLUTION: THREE NUMBERS IN ARITHMETIC PROGRESSION HAVE THE SUM OF 33 AND PRODUCT OF 1232. FIND THE THREE NUMBERS.
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Question 421258: THREE NUMBERS IN ARITHMETIC PROGRESSION HAVE THE SUM OF 33 AND PRODUCT OF 1232. FIND THE THREE NUMBERS.
Answer by dnanos(83) (Show Source): You can put this solution on YOUR website!
Let x-d, x, x+d the unknown numbers.
(x-d)+x+(x+d)=x+x+x=3x
3x=33
x=33/3
x=11
Now we have to find "d":
or
or
(i)for d=3
x-d=8 x=11 x+d=14
(ii)For d=-3
x-d=14 x=11 x+d=8
So the numbers are 8,11 and 14.
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