SOLUTION: Find the first five terms of the sequence for which a(1)=5 and a(n+1)= 3a(n)+1. Thank You

Algebra.Com
Question 41796: Find the first five terms of the sequence for which a(1)=5 and a(n+1)= 3a(n)+1.
Thank You

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
We have
a1 = 5
a2 = 3(a1) + 1 = 16
a3 = 3(a2) + 1 = 49
a4 = 3(a3) + 1 = 148
a5 = 3(a4) + 1 = 445

RELATED QUESTIONS

find the first four terms of the sequence a) a[n]=n^3+1 b) a[1]=4;a[n]=3a[n-1]+1 thank (answered by venugopalramana)
suppose A1=2 and A(n+1)=3A(n)+2. Write the first five terms of the sequence. Then write... (answered by josgarithmetic)
Find the first five terms of each sequence. a. a1 = -4 an = a (n- 1) +... (answered by solver91311)
Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n... (answered by ewatrrr,solver91311)
find the first sixth and twelfth terms of the sequence... (answered by stanbon)
Find the first five terms of the sequence. a(1) =­4, a(n+1) =a(n)... (answered by Alan3354)
How do I write the first four terms of the sequence? a1=1 and a base n = 3a base... (answered by ewatrrr)
Give the first five terms of the sequence in which: {{{a[1]=4}}},{{{a[n+1] =... (answered by Edwin McCravy)
Find the first five terms of the sequence. a(1) =2, a(n+1) =a(n)... (answered by Alan3354)