SOLUTION: in an arithmetic sequence, a3=-8 and a17=48 find the 20th term for the sequence
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Question 399540
:
in an arithmetic sequence, a3=-8 and a17=48
find the 20th term for the sequence
Found 2 solutions by
ewatrrr, rahulsoni001002
:
Answer by
ewatrrr(24785)
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Hi
(8-2d) + 16d = 48
14d = 40
d = 40/14 = 20/7 and
Answer by
rahulsoni001002(1)
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T3=-8, T17=48 and T20=?
Tn=a+(n-1)d
T3=a+(3-1)d
-8=a+2d......(1)
Tn=a+(n-1)d
T17=a+(17-1)d
48=a+16d.....(2)
subtracting (2) from (1)
48=a+16d
-8=a+ 2d
- - -
____________
56= 14d
d=4
-8=a+2d putting d=4
-8=a+2(4)
-8=a+8
a=8+8
a=16
now a=16, d=4 ,T20=?
Tn=a+(n-1)d
T20=16+(20-1)(4)
=16+(19)(4)
=16+76
=92
T20=92
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