# SOLUTION: did I do this right: Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer: r=3 Show work in

Algebra ->  Algebra  -> Sequences-and-series -> SOLUTION: did I do this right: Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer: r=3 Show work in       Log On

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 Algebra: Sequences of numbers, series and how to sum them Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Sequences-and-series Question 39248: did I do this right: Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer: r=3 Show work in this space. each are multiples of 3 1*3=3, 3*3=9, 9*3=27 and so on b) Using the formula for the nth term of a geometric sequence, what is the 10th term? Answer:n=19683 Show work in this space. a(n)=a(1)(r^n-1) a(n)=1(1)*(3^10-1 a(n)=3^9=19683 c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms? Answer: s=29524 Show work in this space. s(n)= a(1)(1-r^n)/1-r s(n)= 1(1)*(1-3^10)/(1-3)=29524Answer by fractalier(2101)   (Show Source): You can put this solution on YOUR website!It all looks good. The only thing I would mention is that the way to find the common ratio of a geometric sequence or series is to merely divide any a-sub-(n+1) term by a-sub-n...