The sequence of denominators is 2, 5, 10, 17, 26, 37, ... and we notice that each term of this sequence is 1 more than the corresponding term in the sequence of squares: 1, 4, 9, 16, 25, 36, ... And we know that the formula for the nth term of that sequence isSo the formula for the nth term of the sequence of denominators 2, 5 10 17, 26, 37, ... is Then the formula for the nth term of the sequence of the absolute values of the terms of the given sequence, 1/2, 1/5, 1/10, 1/17, 1/26, 1/37 is But the signs alternate in the given sequence. To cause the signs to alternate, multiply by the "alternating-sign factor" So the final answer is Edwin