SOLUTION: use s=n^2 to find the sum of 1+3+5+....+501. ------

Question 343949: use s=n^2 to find the sum of 1+3+5+....+501.
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Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the sum of 1+3+5+....+501
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1st find "n" if a(1) = 1 and d = 2
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Using a(n) = a(1) + (n-1)d you get:
501 = 1 + (n-1)2
500 = 2(n-1)
250 = n-1
n = 251
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Find the sum using S(n)=(n/2)(1 + 501)
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S(251) = 251/2(502) = 251*251 = 63001
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cheers,
Stan H.
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