SOLUTION: The next number in the sequence 1, 4/3, 2, 16/5, 16/3, 64/7……. is (A) 128 / 9 (B) 92 / 5 (C) 16 (D) 108 / 7 (E) None of these

Algebra ->  Sequences-and-series -> SOLUTION: The next number in the sequence 1, 4/3, 2, 16/5, 16/3, 64/7……. is (A) 128 / 9 (B) 92 / 5 (C) 16 (D) 108 / 7 (E) None of these       Log On


   



Question 315886: The next number in the sequence 1, 4/3, 2, 16/5, 16/3, 64/7……. is
(A) 128 / 9 (B) 92 / 5 (C) 16 (D) 108 / 7 (E) None of these

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The next number in the sequence 1, 4/3, 2, 16/5, 16/3, 64/7……. is
(A) 128 / 9 (B) 92 / 5 (C) 16 (D) 108 / 7 (E) None of these
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1, 4/3, 2, 16/5, 16/3, 64/7 = 2/2, 4/3, 8/4, 16/5, 32/6, 64/7, then 128/8
= 16
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The numerator is doubled, the denominator is increased by 1.