SOLUTION: How would you solve this equation, x^2 + 2x

SOLUTION: How would you solve this equation, x^2 + 2x - 80 = 0 ?

Question 273969: How would you solve this equation, x^2 + 2x - 80 = 0 ?
Found 2 solutions by Tobiasz, richwmiller:
Answer by Tobiasz(54) (Show Source): You can put this solution on YOUR website!
ok
x * x + 2x -80 = 0
2x + 2x - 80 = 0
4x - 80 = 0
4x = -80 Divide both by 4
x = -20

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=324 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 8, -10. Here's your graph:

RELATED QUESTIONS
How would you solve this equation?... (answered by jim_thompson5910)
How would you solve this equation?... (answered by bucky)
how would you simplify this equation {{{ 4x^2 + 80 = 0}}}? thank... (answered by edjones)
Solve the equation.... (answered by jim_thompson5910)
How would you solve this equation?... (answered by stanbon)
x^2+3x-40=0 How would you solve this... (answered by kapilsinghi,elima)
x^2+3x-40=0 How would you solve this... (answered by kapilsinghi)
I need help!! How would you solve {{{x^2+80=0}}} using... (answered by ankor@dixie-net.com)
-2x^2+x-5=0 how do you solve this... (answered by solver91311)