SOLUTION: The sum of the first n terms in a sequence is always 1/n. Find the product of the first 2007 terms.
Algebra.Com
Question 258765: The sum of the first n terms in a sequence is always 1/n. Find the product of the first 2007 terms.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The sum of the first n terms in a sequence is always 1/n. Find the product of the first 2007 terms.
-----------------------------
2007/n is the number of times you have n terms in 2007
----------------------
Each of those n terms sets adds up to 1/n
------------------------
So the sum is (2007/n)(1/n) = 2007/n^2
=========================================
Cheers,
Stan H.
RELATED QUESTIONS
find the first sixth and twelfth terms of the sequence... (answered by stanbon)
the sum of the n terms of a sequence is 30-10/3^(n-1); n>1
find (a) sum of the first... (answered by Edwin McCravy)
Find the first five terms of the sequence.
a(1) =4, a(n+1) =a(n)... (answered by Alan3354)
Use the geometric sequence of numbers 1, ½, ¼, 1/8,….to find the following:
a) (answered by stanbon)
The sum of the first n terms of an arithmetic squence is given by the formula; Sn= n/2... (answered by edjones)
find the sum of the first two terms of the sequence whose general term is an=(n+2)(n-5). (answered by Love math)
Find the first 5 terms of the sequence defined by a(subscript)n = (-1)^n... (answered by fractalier)
I am having trouble with this problem, could you please help me.
3) Use the geometric... (answered by sdmmadam@yahoo.com)
Given the formula f(n) = 3(-1)n find the first 5 terms of this... (answered by fractalier)