SOLUTION: I am really stuck on this problem. I was hoping someone can help me solve it. (4/3)(-6)(-3/4) Im just not sure how to get the answer. The answer I came up with is 5, but Im n

Algebra.Com
Question 250890: I am really stuck on this problem. I was hoping someone can help me solve it.
(4/3)(-6)(-3/4)
Im just not sure how to get the answer. The answer I came up with is 5, but Im not sure its right!

Answer by dabanfield(803)   (Show Source): You can put this solution on YOUR website!
(4/3)(-6)(-3/4) = ?
Let's do this in two steps:
First (4/3)*(-6) = -24/3
Now multiply -24/3 by -3/4
(-24/3)*(-3/4) = 72/12 = 6
Remember when you multiply two negatives (like -24 and -3) you get a positive.

RELATED QUESTIONS

I am stuck on 3 last questions for my practice exam and was hoping someone can show me... (answered by MathLover1,jorel1380)
Hello there, I was hoping someone could help me work through the steps on this one. I... (answered by Fombitz)
Hello there I was just hoping that someone could help clarify how to solve this quadratic (answered by josgarithmetic)
I have apparently become to reliant on my calculator. I am not sure how to show the work... (answered by ankor@dixie-net.com)
I want to solve {{{x^2+3x-4=0}}} by "completing the square", I have a textbook and some... (answered by stanbon)
Hi all, I was hoping someone could help me answer the followingl; I need to show that the (answered by Alan3354)
Solving Systems of Linear Equations by the Substitution Method. I am having a... (answered by stanbon)
I am not sure if this the right subject to put this under but... I am helping a friend... (answered by solver91311)
How do you solve the inequality (3/4)m - 5/6 ≤ (5/6)m - 3/4? I tried to do this... (answered by ReadingBoosters)