SOLUTION: Find the sum 1+ 1/2+1/4+...+1/1024
an=1+(n-1) ^ -1/2
Algebra.Com
Question 248545: Find the sum 1+ 1/2+1/4+...+1/1024
an=1+(n-1) ^ -1/2
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(1/2)/1=1/2
(1/4)/(1/2)=1/2
r=1/2 Geometric sequence.
(1/2)^(n-1)=1/1024
log[1/2]((1/2)^n-1)=log[1/2](1/1024) Finding n
n-1=10
n=11
Sum of a finite geometric sequence.
=
=.9995/.5
=1.999... the sum
RELATED QUESTIONS
Find the following sum .
(1) {{{Sn = 1/(1*2) + 1/(2*3) +... (answered by ikleyn)
Find the following sum .
(2) {{{ Sn=1/(1*3) + 1/(2*4) + 1/(3*5)... (answered by ikleyn)
Find the sum:[1^1/2] [2^1/2] [3^1/2] ...... (answered by AnlytcPhil)
Use the addition problems below to answer the question.
Based on this pattern, what is... (answered by richwmiller,aditya2117)
find the sum of following series:... (answered by Edwin McCravy)
Find the sum of series {{{ 1 + (1^n/2)C1 + (1^n/3)C2 + (1^n/4)C3 + ...... (answered by ikleyn)
(1)find the sum of 1+1/2+1/3+......+1/n.
(answered by richard1234)
What is the remainder when 2^1024 + 5^1024 +1 is divided by... (answered by richard1234)
Find the sum of the first 100 terms in the series
1/(1*2) + 1/(2*3) + 1/(3*4) + ... +... (answered by ikleyn)