SOLUTION: Find the 345th term of an aritmetic sequence whose 1st term is 4 and whose common difference is 12.

SOLUTION: Find the 345th term of an aritmetic sequence whose 1st term is 4 and whose common difference is 12.

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Question 242961: Find the 345th term of an aritmetic sequence whose 1st term is 4 and whose common difference is 12.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
L=a+(n-1)d
L=4+(345-1)12
L=4+344*12
L=4+4,128
L=4,132 ans.
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