SOLUTION: I need to find the individual totals for 3 months that when added together, equal 88,635. However, each month has a different total which reflects a .0043 percent of increase f

Question 233139: I need to find the individual totals for 3 months that when added together, equal 88,635.
However, each month has a different total which reflects a .0043 percent of increase from that month, to the next month.
Ex. (Month 1 increases by .0043 to get Month 2) (Month 2 increases by .0043 to get Month 3) and all three months equal 88,635.
Does this make sense? Can you help me out? Thanks!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
I need to find the individual totals for 3 months that when added together, equal 88,635.
However, each month has a different total which reflects a .0043 percent of increase from that month, to the next month.
Ex. (Month 1 increases by .0043 to get Month 2) (Month 2 increases by .0043 to get Month 3) and all three months equal 88,635.
:
Change .0043% to a decimal .000043
:
let x = month one total
then
1.000043x = month two
and
1.000043(1.000043x) = month three
:
month 1 + month 2 + month 3 = 88635
x + 1.00043x + 1.000043(1.000043x) = 88635
:
x + 1.00043x + 1.000086x = 88635
:
3.000129x = 88635
:
x =
x = $29,543.73 is month one total
then
1.000043(29543.72) = $29,545.00 is month two total
and
1.000043(29545) = 29546.27 is month three total
;
:
Check by finding the total of the three months.
29543.73 + 29545.00 + 29546.27 = 88635
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