SOLUTION: im suppose to find the sum of the geometric series for 3 -6+12-....to 7 terms and im not quite sure how 2 do that
Algebra.Com
Question 232039: im suppose to find the sum of the geometric series for 3 -6+12-....to 7 terms and im not quite sure how 2 do that
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
I am supposed to find the sum of the geometric series
for 3 -6+12-....to 7 terms
------------------------
Sum Formula: S(n) = a[(r^(n)-1]/[r-1]
----------------------------------------
Your Problem:
a = 3
r = -6/3 = -2
---------------------
S(7) = 3[(-2)^7-1]/[-2-1]
S(7) = 3[-128-1]/[-3]
S(7) = 3[-129]/-3
S(7) = 129
=============================
Cheers,
Stan H.
RELATED QUESTIONS
I'm a high school student in Algebra 2. I have a couple questions,
1. what are the... (answered by stanbon)
-12 1/5 - 3 3/10
Im Not Quite Sure How To DO This Problem. I know i simplify it first
(answered by edjones)
Im stumped!!! Is there an easy way to do these? Thanks so much!
Use the... (answered by Earlsdon)
(Find the equation)well I found the slope of (-4,1)and(2,-2). which is... (answered by scott8148)
Im not sure how im suppose to get the answer for this equation.
It says, Solve for X if... (answered by ewatrrr)
Still do not understand. Please help again.
3) Use the geometric sequence of numbers (answered by stanbon)
Don't know how to do these. Please help.
3) Use the geometric sequence of numbers 1,... (answered by stanbon)
im not quite sure what steps need to be taken to find the answer of the problem (answered by Fombitz)
The sum of the first n squares, given by the sum of the terms 1+4+9+...n^2 can be... (answered by richwmiller)