You can
put this solution on YOUR website!): On the first day Juanita receives 1 dollar. On each succeeding day, she receives 1 dollar more than the total received in all preceding days. On which day will she first receive an amount greater than one hundred dollars?
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1st day 1 = 2^0
2nd day 2 = 2*1
3rd day 4 = 2^2
...
nth day 2^(n-1)
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You want to know what the smallest n is that will produce 2^(n-1)> 100
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Equation: 2^(n-1) = 100
Take the log of both sides to get:
(n-1)log(2) = log(100
(n-1) = log(100)/log(2)
n-1 = 2/log(2) = 6.644
n = 7.644
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She will receive more than 100 on the 8th day and beyond.
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Cheers,
Stan H.
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(A) 6th day (B) 7th day (C) 8th day (D) 9th day (E) 10th day
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