SOLUTION: Find the sum of each infinite geometric series. 32. 30 + 22.5 + 16.875 + . . . Sn=a/(1-r) r = 0.75 a = 30 Sn = 120 33. 15 - 3 + 0.6 - 0.12 + . . .

SOLUTION: Find the sum of each infinite geometric series. 32. 30 + 22.5 + 16.875 + . . . Sn=a/(1-r) r = 0.75 a = 30 Sn = 120 33. 15 - 3 + 0.6 - 0.12 + . . .

Algebra.Com

Question 196907: Find the sum of each infinite geometric series.

32. 30 + 22.5 + 16.875 + . . .
Sn=a/(1-r)
r = 0.75
a = 30
Sn = 120
33. 15 - 3 + 0.6 - 0.12 + . . .
r = -0.2
a = 15
Sn = 12.5
34. 12 + 6 + 3 + . . .
a = 12
r = 0.5
Sn = 24

Answer by mathsteacher(28) (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS
for part (a) find the sum of the first n terms of the arithmetic series. for part (b)... (answered by mathstutor458,KMST)

Find the sum of each infinite geometric series 35. 4 -2 + 1 -1/2+... common ratio = (answered by mathsteacher)

write the first six terms of the sequence 2. an=(n+1)^3 4. an=n/n+3 write the next (answered by richard1234)

Find the partial sum Sn of the geometric sequence that satisfies the given conditions. a (answered by ikleyn)

Find the sum of the infinite geometric series 3/5-1/5+1/15-1/45+... 1+1/4+1/16+... (answered by jim_thompson5910)

determine the number of terms n in each geometric series. Given that a1=3 r=6 and... (answered by greenestamps)

What is Sn of the geometric series with a1=-81, r=-2/3, and n=5? A)26 B) -39 C) -55 (answered by richwmiller)

please help me. this is my last resort 1. Find the midpoint and... (answered by Fombitz)

How do I find a1 for the geometric series Sn= 31.5 an= -4 r=-6? (answered by robertb)