Question 196326This question is from textbook
: Barbara has nickels, dimes, and quarters, worth $2.35 in her purse. The number of dimes is three less then sum of the numbers of nickels and quarters. How many of each type of coin does she have if there are 19 coins in all.
How would I even began to solve this? the chapter is about system of eyations with three variables, so there's a clue.This question is from textbook
Answer by solver91311(12126)   (Show Source):
You can put this solution on YOUR website!
Let n represent the number of nickels.
Let d represent the number of dimes.
Let q represent the number of quarters.
Ok, that's three variables -- seems like a good start. Now let's see what we can do about three equations.
We know that there are 19 coins in all, so:
That's our first equation.
And we know that the number of dimes is three less than the sum of the numbers of nickels and quarters, so:
And that's our second equation.
We also know that the total amount of money is $2.35, which can also be expressed as 235 cents. Furthermore, nickels are worth 5 cents each, dimes 10 cents each, and quarters are 25 cents each. So the values of her coins are:
 is the value of the nickels
 is the value of the dimes, and
 is the value of the quarters; all values expressed in cents, so:
which is the third equation.
Solve the system for n, d, and q and you will have your answer.
John
|
|
|
