SOLUTION: find three numbers in arithmetic progression whose sum is 21 and whose product is 180?

SOLUTION: find three numbers in arithmetic progression whose sum is 21 and whose product is 180?

Algebra.Com

Question 192687: find three numbers in arithmetic progression whose sum is 21 and whose product is 180?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

If the arithmetic progression has a common difference of d, and the first of the three numbers is x, then the second number must be x + d and the third, x + 2d.

So if the sum is 21, then:

is the first number,

is the second number, and

is the third number.

Now, if the product is 180, then:

Rationalizing the denominator:

and the three numbers are:

,

, and

.

John

RELATED QUESTIONS
find three numbers in arithmetic progression whose sum is 21 and whose product is... (answered by stanbon,RAY100)

Find three numbers in arithmetic progression whose sum and product are six and six... (answered by ikleyn)

find three numbers in geometric progression whose sum is 19 and product is... (answered by ramkikk66)

find three numbers in geometric progression whose sum is 19 and product is... (answered by ramkikk66)

find the three numbers in an arithmetic progression whose sum is 48 and the sum of their... (answered by ikleyn)

Find 3 numbers in the geometrical progression whose sum is 28 and whose product is... (answered by ikleyn)

Find three numbers in geometric progression whose sum is 21 and sum of their squares is... (answered by texttutoring)

Pls Help me with this question urgently,thanks. Find the three numbers in a... (answered by Edwin McCravy)

Find 3 number in the geometrical progression whose sum is 28 and whose product is... (answered by swincher4391,Alan3354)