SOLUTION: i need to know the steps on how to do this problem: for each geometric series, find the sum. if the series has no sum, say so. 1. 24+12+6+3+...

Question 189127This question is from textbook algebra and trigonometry
: i need to know the steps on how to do this problem:
for each geometric series, find the sum. if the series has no sum, say so.

1. 24+12+6+3+... This question is from textbook algebra and trigonometry

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
for each geometric series, find the sum. if the series has no sum, say so
----
24+12+6+3+...
a(1) = 24
---
r = 12/24 = 1/2
------------------
S(n) = a[1-r^n]/[1-r]
----
Limit as n goes to infinity : S(n) = a/(1-r)
----
Your problem:
Sum = 24/(1-(1/2)) = 24/(1/2) = 48
========================================
Cheers,
Stan H.
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