You can
put this solution on YOUR website!Take note that the first term is
, the second term is
, etc.
So the fourth term is
where
So when
, then
(the previous term),
(the next previous term), and
(the next previous term)
a_{n-2}+\left(\frac{1}{3}\right)a_{n-3})
Start with the given equation
a_{2}+\left(\frac{1}{3}\right)a_{1})
Plug in
,
,
, and
(see above)
(3)+\left(\frac{1}{3}\right)1)
Plug in
,
, and
(these are given)
Multiply
Combine the fractions.
So the 4th term is
(