SOLUTION: find the sum of the geometric series
6
[SUM] 2^n
n=1
n=1 2^1=2
n=2 2^2=4
n=3 2^3=8
n=4 2^4=16
n=5 2^5=32
n=6 2^6=64
2+4+8+16+32+64= 126
am I doing this correctl
Algebra.Com
Question 149421: find the sum of the geometric series
6
[SUM] 2^n
n=1
n=1 2^1=2
n=2 2^2=4
n=3 2^3=8
n=4 2^4=16
n=5 2^5=32
n=6 2^6=64
2+4+8+16+32+64= 126
am I doing this correctly?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You got it. Good job.
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1. A(n)=-3+(n-1)(5)
2. A(n)=-11+(n-1)(2)
3. A(n)=9+(n-1)(8)
4. A(n)=0.5+(n-1)(3.5)
(answered by tommyt3rd)
1. A(n)=-3+(n-1)(5)
2. A(n)=-11+(n-1)(2)
3. A(n)=9+(n-1)(8)
4. A(n)=0.5+(n-1)(3.5)
(answered by tommyt3rd)