Show that if the sum of an arithmetic series with an odd number of terms is 0, then one of the terms of the series must be 0. (Hint: let the number of terms be 2k + 1. Show that a1 = -kd. Then find the (k + 1)st term.)
Sn = 0 (given)
Sn = [2a1 + (n-1)d] (formula for sum of the first n terms)
[2a1 + (n-1)d] = 0 (Both sides equal Sn)
2a1 + (n-1)d = 0 (Divide both sides by
2a1 + (2k+1-1)d = 0 (Substitute 2k+1 for n)
2a1 + 2kd = 0 (Simplification)
2a1 = -2kd (Subtract 2kd from both sides
a1 = -kd (Divide both sides by 2)
Now we find ak+1
an = a1 + (n-1)d (Formula for the nth term)
ak+1 = -kd + (k+1-1)d (Substituting k+1 for n
and -kd for a1
ak+1 = -kd + kd (Simplification)
ak+1 = 0 (Simplification)
Edwin