SOLUTION: Find the sum of the first fifteen terms of the geometric series: 2-3+4.5-6.75+10.125

SOLUTION: Find the sum of the first fifteen terms of the geometric series: 2-3+4.5-6.75+10.125

Algebra.Com

Question 137345: Find the sum of the first fifteen terms of the geometric series:
2-3+4.5-6.75+10.125
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the sum of the first fifteen terms of the geometric series:
2-3+4.5-6.75+10.125
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r = -3/2
S(15) = 2 * [(-3/2)^15 -1] / [(-3/2)-1] = 351.1151123...
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Cheers,
Stan H.
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