SOLUTION: If the average (arithmetic mean) of 5 consecutive integers is 12, what is the sum of the least and greatest of the 5 integers? 5 numbers (x1,x2, x3, x4, x5)=60 x=

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Question 123866: If the average (arithmetic mean) of 5 consecutive integers is 12, what is the sum of the least and greatest of the 5 integers?
5 numbers (x1,x2, x3, x4, x5)=60
x=
Answer by solver91311(12126) About Me  (Show Source):
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If you have 5 consecutive integers, call the first one x, then the second is x + 1, the third is x + 2, etc.

The sum of these 5 numbers divided by 5 is 12, so their sum must be 60, so:

x%2B%28x%2B1%29%2B%28x%2B2%29%2B%28x%2B3%29%2B%28x%2B4%29=60
5x%2B10=60
5x=50
x=10

Therefore the numbers are 10, 11, 12, 13, and 14. The least is 10 and the greatest is 14. Their sum is 24.