The given series is
a+ar+ar^2+ar^3+...
The sum of the series is 3:
[1]
The series consisting of the cubes of the terms of the given series is
a^3r^3+a^3r^6+a^3r^9+...
The sum of that series is 5:
[2]
To find the common ratio r, solve [1] for a in terms of r and substitute in [2].
By inspection, r=1 is one solution to that equation. However r=1 produces an infinite geometric series that has no sum.
Use synthetic division to remove the root x=1 to find the other two roots.
1 | 22 -81 81 -22
| 22 -59 22
+---------------
22 -59 22 0
The remaining quadratic is
Use the quadratic formula to find that the other two solutions are
There are two possible values for the common ratio r:
ANSWERS: