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a theater has 20 rows of chairs the first row has 10 chairs and each row after that
has 2 more seats than the row before it. How many total seats are in the theater?
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The series of the chairs in rows is an arithmetic progression.
1-st row has 10 chairs.
The last, 20th row has 10 + (20-1)*2 = 10 + 19*2 = 10 + 38 = 48 chairs.
(use the formula for the n-th term of an AP).
In all, there are = = = 58*10 = 580 chairs.
(use the formula for the sum of the first n terms of an AP).
Solved.
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For introductory lessons on arithmetic progressions see
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
in this site.