SOLUTION: The first and the last term of an arithmetic progression are -0.5 and 140.5 respectively. If the number of terms in the sequence is 48, find it's common difference

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Question 1204114: The first and the last term of an arithmetic progression are -0.5 and 140.5 respectively. If the number of terms in the sequence is 48, find it's common difference
Found 4 solutions by math_tutor2020, greenestamps, Edwin McCravy, MathTherapy:
Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

= first term = -0.5
= 48th term = 140.5
= nth term
n = number of terms = 48
d = common difference



















is the common difference
Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Informally....

The difference between the first and last terms is 140.5-(-.5) = 141.

There are 48 terms in the sequence, which means the last term is 47 terms after the first.

The common difference in the sequence is then 141/47 = 3.

ANSWER: 3
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
As an enrichment fact, to show a connection between things learned
separately in algebra:

It's also the slope of the line through (1,-0.5) and (48,140.5)











Edwin
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
The first and the last term of an arithmetic progression are -0.5 and 140.5 respectively. If the number of terms in the sequence is 48, find it's common difference 

Common difference (d) =


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