SOLUTION: What is the infinite sum from k-1 to infinity of (-6÷7)^k-1

Question 1197590: What is the infinite sum from k-1 to infinity of (-6÷7)^k-1
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

The common ratio is (-6/7); the absolute value of that ratio is less than 1, so the infinite sum exists.

The formula for the sum of an infinite geometric progression is

            first term
  -------------------------------
   1 minus the common difference

The first term and the common difference are both (-6/7). You can do the simple calculation yourself.

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