SOLUTION: Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 10 more than three times the largest number.

Question 1193931: Find three consecutive whole numbers such that twice the sum of the two smallest numbers is 10 more than three times the largest number.
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.
Find three consecutive whole numbers such that twice the sum of the two smallest numbers
is 10 more than three times the largest number.
~~~~~~~~~~~~~~

Let the numbers be n, (n+1) and (n+2).


Write equation as you read the problem

    2*(n + (n+1)) = 3*(n+2) + 10.


Now simplify and find "n"

    2n + 2n + 2 = 3n + 6 + 10

    4n + 2 = 3n + 16

    4n - 3n = 16 - 2

       n    =    14


ANSWER.  The numbers are 14, 15 and 16.

Solved, answered and explained.

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