SOLUTION: The first three terms of a GP are p-5,2p-6 and 4p-5.Determine:
1.The value of p.
2.The sum of the values.
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Question 1182616: The first three terms of a GP are p-5,2p-6 and 4p-5.Determine:
1.The value of p.
2.The sum of the values.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
In a GP, the ratio of consecutive terms is constant:
Cross multiplying gives
Note a slightly faster way to get to that equation is to use the fact that, for any three consecutive terms of a GP, the product of the first and third is the square of the second:
Continuing....
1. ANSWER: p = -11
The three terms are
p-5 = -16
2p-6 = -28
4p-5 = -49
We can verify that those numbers form a GP:
-28/-16 = 7/4
-49/-28 = 7/4
2. ANSWER: the sum of the three terms is (-16)+(-28)+(-49)=-93
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