SOLUTION: consider the sequence of numbers: 2;5;2;9;2;13;2;17 calculate the sum of the first 100 terms of the sequence

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Question 1177107: consider the sequence of numbers: 2;5;2;9;2;13;2;17
calculate the sum of the first 100 terms of the sequence

Found 2 solutions by mccravyedwin, MathLover1:
Answer by mccravyedwin(407)   (Show Source): You can put this solution on YOUR website!
2,5,2,9,2,13,2,17,...

The sum of the 50 odd numbered terms 

2,_,2,_,2,_,2,_,...2

is 50*2 = 100  <--sum of odd numbered terms (all 2's)

-------------------------

The sum of the 50 even-numbered terms:

5,__,9,__,13,__,17,__,...

That's 50 terms of an arithmetic sequence with common difference 4:











  <--sum of even-numbered terms.

------------------

Add them together = 100 + 5150 = 5250  <--answer

Edwin

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
,,,,,,,,...
pattern:
all odd number terms are equal,
in terms you have of them; so their sum is
all even number terms, you also have of them, have common difference ;




and so on, and the formula for nth term of an arithmetic progression is
where and


so.
sum of all even number terms is:




add both odd and even terms sums

->the sum of the first terms


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