SOLUTION: Find the sum in terms of n for
n
∑ {{{ (3k^2-5k+7) }}}
k=1
Given:
n
∑= {{{ (n(n+1)(2n+1))/6 }}}
k=1
n
∑= {{{ (n(n+1))/2 }}}
k=1
Algebra.Com
Question 1177007: Find the sum in terms of n for
n
∑
k=1
Given:
n
∑=
k=1
n
∑=
k=1
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Your presentation of the problem is flawed; the information as given is nonsense.
I don't know if you posted it incorrectly, or if it was incorrect when it was given to you.
When the problem is presented correctly, the solution is simple.
---------------------------------------------------------
Here is how the problem should have been posted:
Find the sum in terms of n for
Given:
(The "k^2" was missing in your post, making the statement meaningless)
and
(likewise, the "k" was missing)
It should also be obvious that
Then...
Then simplify if required.
RELATED QUESTIONS
Prove that
{{{6/(n+1) <= 6/(2n+1) +sqrt(sum(1/k^2, k=1,n))}}} for {{{n >=... (answered by Edwin McCravy)
n!(n+2)=n!+(n+1)!
(answered by LinnW)
2+4+6+.....2n=n(n+1) (answered by ikleyn)
Let {{{N = N[1] + N[2]}}} , and {{{1 <= k <= N[1]}}} and {{{1 <= k <= N[2]}}}.
Prove... (answered by robertb)
Find a and b if {{{sum( ak+b, k=1, n ) = 8n^2+11n}}}, given that {{{sum( k, k=1, n ) =... (answered by Edwin McCravy,Bakr.R)
-k^2-(3k-5n)+4n ; k= -1 ; n=... (answered by solver91311)
find the sum of following series:... (answered by Edwin McCravy)
Find the value of n for which... (answered by scott8148)
Prove that: {{{sum((2k-1^"")^""^""^"",k=1,n)}}}{{{""=""}}}{{{sum(... (answered by Edwin McCravy)