.
For it, you should have
= , or
= , or, cross multiplying
(5k+1)*(2k+1) = , or, simplifying
10k^2 + 7k + 1 = 9k^2 + 6k + 1
k^2 + k = 0
k(k+1) = 0
k= 0 OR k= -1.
At k= 0, the three terms of the GP are 1, 1, 1.
At k = -1, the three terms of the GP are -1, -2, -4.
So, there are 2 possibilities.
One geometric progression is {1, 1, 1,}. It corresponds to the value of k= 0.
Another geometric progression is {-1, -2, -4}. It corresponds to the value of k= -1.
Solved.
---------------
On geometric progressions, see introductory lessons
- Geometric progressions
- The proofs of the formulas for geometric progressions
- Problems on geometric progressions
- Word problems on geometric progressions
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic
"Geometric progressions".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.