.
You have two ways.
First way is to notice that the numbers are
25 logs (1-st, bottom pile)
23 logs (2-nd, next pile)
21 logs (3-rd pile)
19 logs
. . . . .
25-2*(13-1) = 25-2*12 = 25-24 = 1 log (13-th pile)
Then to add the numbers 25 + 23 + 21 + 19 + . . . + 1 manually or using your calculator.
For it, there is no need to watch YouTube videos, at all.
But if you know what an arithmetic progression is, you may apply formulas for summing its terms.
You have 13 terms; the first term is = 25; the last, 13-th term is = 1.
Hence, the sum of the thirteen terms is = = = = 13*13 = 169.
The last step is to multiply 57 kilograms by 169.
Solved and explained.
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For introductory lessons on arithmetic progressions see
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.