SOLUTION: An arithmetic sequence starts 23, 36, 49, 62, …. What is the first term of the sequence to exceed 200,000?

Algebra.Com
Question 1165705: An arithmetic sequence starts 23, 36, 49, 62, …. What is the first term of the sequence to exceed 200,000?
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.

First term of the AP is 23;  the common difference is 13.


You want to find the minimal integer "n" such that


    23 + 13*(n-1) >= 200000.


Then  n-1 >=  = 15382.85;  hence, n = 15383 + 1 = 15384.      ANSWER


CHECK.  23 + 13*(15384-1) = 200002.     ! Ok !

Solved, answered and explained.



RELATED QUESTIONS

The third term of an arithmetic sequence is 4 and the sum of the first 8 term is 36.... (answered by drj)
Given an arithmetic sequence -11,2,15..., if T(m) is the first term that exceeds 200,... (answered by rothauserc)
in an arithmetic sequence the ratio of first term to second term is 2:3 .what is the... (answered by richwmiller)
THE 75TH TERM OF AN ARITHMETIC SEQUENCE IS 301. THE FIRST TERM IS 5. WHAT IS THE COMMON... (answered by drk)
The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the... (answered by MathLover1,MathTherapy,greenestamps,ikleyn)
The sum of the first n terms of an arithmetic sequence is (2n^2)-n. Find the general term (answered by MathLover1)
1) Use the explicit formula an=(-1)^n(13n-6), to find the first five terms of the... (answered by ikleyn)
Write an equation for the nth term of the given arithmetic sequence. - 14, - 30, -... (answered by Boreal)
what is the nth term of an arithmetic sequence, what is the 101st term... (answered by stanbon)