.
The sum of the first 4 terms is + + + .
The sum of the next 4 terms is + + + .
Each difference , , and is equal to 4d,
where d is the common difference of the AP.
Therefore, 4*(4d) = 74 - 26, or 16d = 48; hence, d = 48/16 = 3.
Next, 26 = 4a + (1+2+3)d = 4a + 6*3 = 4a + 18, which implies
4a = 26 - 18 = 8.
Answer. The first term of the AP is 8/4 = 2; the common difference is 3.
Solved.
The goal of this problem is to teach you manipulate with AP terms quickly and informally.
It is a simple problem; so, the method of its solution should be adequately simple.
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On arithmetic progressions, see the lessons
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
- One characteristic property of arithmetic progressions
- Solved problems on arithmetic progressions
- Calculating partial sums of arithmetic progressions
- Finding number of terms of an arithmetic progression
- Advanced problems on arithmetic progressions
- Problems on arithmetic progressions solved MENTALLY
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".
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