The 4-th term = sum of the first 4 terms MINUS sum of the first 3 terms = = (4^2-3*4) - (3^2-3*3) = (16-12) - (9-9) = 4 - 0 = 4. ANSWER The n-th term = sum of the first "n" terms MINUS sum of the first (n-1) terms = = (n^2-3*n) - ((n-1)^2-3*(n-1)). Simplify to get the answer.