SOLUTION: Write each series as a summation in sigma notation.
10+20+40+80
Algebra.Com
Question 1151137: Write each series as a summation in sigma notation.
10+20+40+80
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Answer: ^{k-1}}})
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More explanation:
If you plugged in k = 1, you'd get ^{k-1} = 10(2)^{1-1} = 10)
as the first term.
If you plugged in k = 2, you'd get ^{k-1} = 10(2)^{2-1} = 20)
as the second term.
If you plugged in k = 3, you'd get ^{k-1} = 10(2)^{3-1} = 40)
as the third term.
If you plugged in k = 4, you'd get ^{k-1} = 10(2)^{4-1} = 80)
as the fourth term.
So, ^{k-1} = 10 + 20 + 40 + 80)
The sequence 10, 20, 40, 80, ... is geometric with
a = first term = 10
r = common ratio = 2
The general nth term of a geometric sequence is ^{n-1})
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