(1) Notice that the sum of 99 consecutive odd integers is 99 times the average of the first and the last numbers in this sequence. (2) In other words, the sum of 99 consecutive odd integers is 99 times half the sum of the first and the last numbers in this sequence. (3)= 99.99997... (approximately) It means that the greatest perfect cube less than 999999 is . (4) Thus the condition says = . (5) Hence, + = = 19602. It is the ANSWER to the problem's question.