SOLUTION: check the formula is correct for k=1,2, and 3 k (sigma)n^2 = k(k+1)(2k+1)/6 n=0 use the formula given in the problem above to compute the value of 5 (Sigma) (2m^2+3m-4) m=0

Question 1131970: check the formula is correct for k=1,2, and 3
k
(sigma)n^2 = k(k+1)(2k+1)/6
n=0
use the formula given in the problem above to compute the value of
5
(Sigma) (2m^2+3m-4)
m=0
Answer by Edwin McCravy(20056) (Show Source): You can put this solution on YOUR website!



k=1



k=2



k=3



---------------------------------------------



The preceding two steps involved (A) taking out a constant coefficient,
and (B) introducing a multiplier of 1 so we would have a constant
coefficient of -4 to take out.  But from here we need two other summation
formulas, which are:

         and 





Edwin

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