SOLUTION: show that the general term of the sequence -2/5,1/0,4/15,7/20,0/25,...can be written as Tn =3n -5/5n

Question 1127085: show that the general term of the sequence -2/5,1/0,4/15,7/20,0/25,...can be written as Tn =3n -5/5n
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
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What is 1/0, the second term of the sequence ?

For your info, in Math, it is prohibited to divide by zero.

Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Given the form for Tn, it is clear that you have a typo in the given sequence. The second term is 1/10, not 1/0; the 5th term is 10/25, not 0/25.

It would be polite (and beneficial to you) for you to look at what you have written in your post before submitting it.

Then there is not much to show....

The numerators are -2, 1, 4, 7, 10,...; they follow the pattern 3n-5. The denominators are 5, 10, 15, 20, 25,...; they follow the pattern 5n.

So the fractions follow the pattern (3n-5)/(5n).
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