.
The sum of the first n terms of an arithmetic progression (of any arithmetic progression) is
= .
This formula ideally suits to solve the given problem, since the terms and are given in the condition.
So, in your case
1550 = = = 50n,
which gives you the number of the terms n = = 31.
Answer. There are 31 terms in the given AP.
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There is a bunch of lessons on arithmetic progressions in this site:
- Arithmetic progressions
- The proofs of the formulas for arithmetic progressions
- Problems on arithmetic progressions
- Word problems on arithmetic progressions
- One characteristic property of arithmetic progressions
- Solved problems on arithmetic progressions
- Math Olimpiad level problem on arithmetic progression
- Mathematical induction and arithmetic progressions
- Mathematical induction for sequences other than arithmetic or geometric
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Arithmetic progressions".
Save the link to this textbook together with its description
Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson
into your archive and use when it is needed.
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Regarding your second problem in the post, there is A GOLDEN RULE in this forum, which is the policy
and the requirement in the same time:
ONE and ONLY ONE problem per post